A triangle has corners at (3 , 4 )(3,4), (5 ,6 )(5,6), and (2 ,1 )(2,1). What is the radius of the triangle's inscribed circle?

1 Answer
Jun 23, 2017

The radius is =0.34=0.34

Explanation:

The area of the triangle is

A=1/2|(x_1,y_1,1),(x_2,y_2,1),(x_3,y_3,1)|

A=1/2|(3,4,1),(5,6,1),(2,1,1)|

=1/2(3*|(6,1),(1,1)|-4*|(5,1),(2,1)|+1*|(5,6),(2,1)|)

=1/2(3(6-1)-4(5-2)+1(5-12))

=1/2(15-12-7)

=1/2|-4|=2

The length of the sides of the triangle are

a=sqrt((5-3)^2+(6-4^2))=sqrt(8)

b=sqrt((5-2)^2+(6-1)^2)=sqrt34

c=sqrt((3-2)^2+(4-1)^2)=sqrt10

Let the radius of the incircle be =r

Then,

The area of the circle is

A=1/2r(a+b+c)

The radius of the incircle is

r=(2a)/(a+b+c)

=(2*2)/(sqrt8+sqrt34+sqrt10)

=0.34