A triangle has corners at $(3 , 4 )$ , $(8 ,2 )$ , and $(1 ,3 )$ . What is the radius of the triangle's inscribed circle?

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Answer 1 · 2017-07-19T16:21:43

The radius of the incircle is $=0.61u$

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The length of the sides of the triangle are

$c=sqrt((8-3)^2+(2-4)^2)=sqrt(25+4)=sqrt29=5.39$

$a=sqrt((1-8)^2+(3-2)^2)=sqrt(49+1)=sqrt50=7.07$

$b=sqrt((3-1)^2+(4-3)^2)=sqrt(4+1)=sqrt5=2.24$

The area of the triangle is

$A=1/2|(x_1,y_1,1),(x_2,y_2,1),(x_3,y_3,1)|$

$=1/2(x_1(y_2-y_3)-y_1(x_2-x_3)+(x_2y_3-x_3y_2))$

$A=1/2|(3,4,1),(8,2,1),(1,3,1)|$

$=1/2(3*|(2,1),(3,1)|-4*|(8,1),(1,1)|+1*|(8,2),(1,3)|)$

$=1/2(3(2-3)-4(8-1)+1(24-2))$

$=1/2(-3-28+22)$

$=1/2|-9|=9/2$

The radius of the incircle is $=r$

$1/2*r*(a+b+c)=A$

$r=(2A)/(a+b+c)$

$=9/(14.7)=0.61$

A triangle has corners at (3 , 4 )(3 , 4 ), (8 ,2 )(8 ,2 ), and (1 ,3 )(1 ,3 ). What is the radius of the triangle's inscribed circle?