If the sides of a triangle are aa, bb and cc, then the area of the triangle Delta is given by the formula
Delta=sqrt(s(s-a)(s-b)(s-c)), where s=1/2(a+b+c)
and radius of circumscribed circle is (abc)/(4Delta)
Hence let us find the sides of triangle formed by (4,4), (8,9) and (3,1). This will be surely distance between pair of points, which is
a=sqrt((8-4)^2+(9-4)^2)=sqrt(16+25)=sqrt41=6.4031
b=sqrt((3-8)^2+(1-9)^2)=sqrt(25+64)=sqrt89=9.4340 and
c=sqrt((3-4)^2+(1-4)^2)=sqrt(1+9)=sqrt10=3.1623
Hence s=1/2(6.4031+9.4340+3.1623)=1/2xx18.9994=9.4997
and Delta=sqrt(9.4997xx(9.4997-6.4031)xx(9.4997-9.4340)xx(9.4997-3.1623)
= sqrt(9.4997xx3.0966xx0.0657xx6.3374)=sqrt12.2482=3.4997
And radius of circumscribed circle is
(6.4031xx9.4340xx3.1623)/(4xx3.4997)=13.6458
And area of circumscribed circle is 3.1416xx(13.6458)^2=584.99