Question

A triangle has corners at `(6 ,1 )`, `(5 ,7 )`, and `(3 ,8 )`. How far is the triangle's centroid from the origin?

Answer 1

`(1/3)sqrt452~=7.09.`

Explanation:

Centroid `G` is `G((6+5+3)/3, (1+7+8)/3) = G(14/3, 16/3)`, & the Origin `O` is `O(0,0).`

The distance `d` between these points, using the distance formula,
`d= sqrt{(14/3)^2+(16/3)^2}=(1/3)sqrt(196+256)=(1/3)sqrt452~=(1/3)(21.26)~=7.09.`