A triangle has corners at (7,7), (1,3), and (6,5). What is the area of the triangle's circumscribed circle?

1 Answer

Area of the circum circle is 158.503

Explanation:

Midpoint of corners (7,7)and(1,3) is given by
(7+32,7+12)
=(5,4)
Slope of the line between the corners (7,7)and(1,3) is given by
3717
=46
=23
Slope of the perpendicular bisector for the line between the corners (7,7)and(1,3) is given by
=123
=32
We have the equation of the perpendicular bisector for the line between the corners (7,7)and(1,3) given by
Point (5,4)
Slope 32
point slope form is
y4x5=32

Midpoint of corners (1,3)and(6,5) is given by
(1+62,3+52)
=(3.5,4)
Slope of the line between the corners (1,3)and(6,5) is given by
5361
=25
=25
Slope of the perpendicular bisector for the line between the corners (1,3)and(6,5) is given by
=125
=52
We have the equation of the perpendicular bisector for the line between the corners (1,3)and(6,5) given by
Point (3.5,4)
Slope 52
point slope form is
y4x3.5=52

Solving for the center of the circumcircle
y4x5=32
2(y4)=3(x5)
2y8=3x+15
2y+3x158=0
3x+2y23=0

y4x3.5=52
2(y4)=5(x3.5)
2(y4)+5(x3.5)=0
2y8+5x17.5=0
5x+2y24.5=0

We have,
3x+2y23=0
5x+2y24.5=0
Eliminating y
3x5x23+24.5=0
2x+1.5=0
2x=1.5
x=0.75
Substituting
3(0.75)+2y23=0
2.25+2y23=0
Simplifying
2y=232.25
2y=20.75
y=10.375
Center for the circum circle has the coordinates
(0.75,10.375)
Radius r=distance from center to vertex
(0.75,10.375)(7,7)
Area of the circum circle is
A=πr2
π=3.141
r2=(70.75)2+(710.375)2
r2=(6.25)2+(3.375)2
r2=50.453
Hence, Area is
A=3.14150.453
Area of the circum circle is 158.503