A triangle has corners points A, B, and C. Side AB has a length of 9 9. The distance between the intersection of point A's angle bisector with side BC and point B is 6 6. If side AC has a length of 10 10, what is the length of side BC?

1 Answer

Side BC=12 2/3=12.6666" "BC=1223=12.6666 units

Explanation:

There is a theorem in Geometry which states ,"An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle."

Let the intersection be point II

Therefore, our equation is as follows
AB:IB=AC:ICAB:IB=AC:IC

(AB)/(IB)=(AC)/(IC)ABIB=ACIC

9/6=10/(IC)96=10IC

IC=(6(10))/9IC=6(10)9

IC=20/3IC=203

The length of BC=IB+ICBC=IB+IC

BC=6+20/3BC=6+203

BC=38/3=12 2/3BC=383=1223

God bless...I hope the explanation is useful.