A triangle has two corners with angles of # (2 pi ) / 3 # and # ( pi )/ 6 #. If one side of the triangle has a length of #1 #, what is the largest possible area of the triangle?

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Answer 1 · 2017-12-08T15:02:27

Largest possible area of the triangle is 0.433

Given are the two angles #(2pi)/3# and #pi/6# and the length 1

The remaining angle:

#= pi - ((2pi)/3) + pi/6) = (pi)/6#

I am assuming that length AB (1) is opposite the smallest angle.

Using the ASA

Area#=(c^2*sin(A)*sin(B))/(2*sin(C)#

Area#=( 1^2*sin(pi/6)*sin((2pi)/3))/(2*sin(pi/6))#

Area#=0.433#