A triangle has two corners with angles of π12 and π4. If one side of the triangle has a length of 12, what is the largest possible area of the triangle?

1 Answer
Dec 11, 2017

Largest possible area of the triangle is 170.3538

Explanation:

Given are the two angles π12 and π4 and the length 1

The remaining angle:

=π(π4)+π12)=2π3

I am assuming that length AB (12) is opposite the smallest angle.

Using the ASA

Area=c2sin(A)sin(B)2sin(C)

Area=122sin(π4)sin(2π3)2sin(π12)

Area=170.3538