A triangle has two corners with angles of π3 and π6. If one side of the triangle has a length of 12, what is the largest possible area of the triangle?

1 Answer
Dec 7, 2017

723square units

Explanation:

First, we know that the angels of a triangle has to add up to π. Therefore, we know that the leftover angle is π(π3+π6)=π2 which is a right angle. Therefore, we know that the triangle is a right triangle. We also know that this is the special "30-60-90" triangle. Therefore, we can figure out the sides while assuming 12 being one of each: the shortest, the middle, the longest.

Remember that in a "30-60-90" triangle, the shortest side is a, the second longest (middle) side is a3 and the longest side is 2a.
Also, you multiply the two legs and then divide it by two to find the area of a right triangle.

When 12 is the hypotenuse, we know that the shortest side is 6 and the middle side is 63 with the area of 183

When 12 is the shortest side, we don't really care about the hypotenuse. The middle side is 123 with the area of 723.

When 12 is the middle side, we again don't care about the hypotenuse. The shortest side would be 123 which really is 43 with the area of 243. Out of these three, we see that 723 is the largest possible area.