A truck pulls boxes up an incline plane. The truck can exert a maximum force of $2, 500 N$ $2,500 N$ . If the plane's incline is $\frac{3 π}{8}$ $(3 pi )/8$ and the coefficient of friction is $\frac{1}{7}$ $1/7$ , what is the maximum mass that can be pulled up at one time?

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A truck pulls boxes up an incline plane. The truck can exert a maximum force of $2, 500 N$ $2,500 N$ . If the plane's incline is $\frac{3 π}{8}$ $(3 pi )/8$ and the coefficient of friction is $\frac{1}{7}$ $1/7$ , what is the maximum mass that can be pulled up at one time?

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Answer 1 · 2016-04-06T13:54:57

Here
Force of gravitational pull along inclined plane + force of friction = Total maximum force
If maximum mass pulled = $m k g$ $mkg$
Force of gravitational pull along inclined plane $= m g sin θ$ $=mgsintheta$
force of friction $= μ m g cos θ$ $=mumgcostheta$

$m g sin θ + μ m g cos θ = 2500$ $mgsintheta +mumg costheta =2500$

$m \times 9.8 \times (sin (3 \frac{π}{8}) + \frac{1}{7} \times cos (3 \frac{π}{8})) = 2500$ $mxx9.8xx(sin(3pi/8)+1/7xxcos(3pi/8))=2500$
$m = 274 k g$ $m=274kg$

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A truck pulls boxes up an incline plane. The truck can exert a maximum force of $2, 500 N$ $2,500 N$ . If the plane's incline is $\frac{3 π}{8}$ $(3 pi )/8$ and the coefficient of friction is $\frac{1}{7}$ $1/7$ , what is the maximum mass that can be pulled up at one time?

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A truck pulls boxes up an incline plane. The truck can exert a maximum force of 2,500N2,500 N. If the plane's incline is 3π8(3 pi )/8 and the coefficient of friction is 171/7 , what is the maximum mass that can be pulled up at one time?

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A truck pulls boxes up an incline plane. The truck can exert a maximum force of $2, 500 N$ $2,500 N$ . If the plane's incline is $\frac{3 π}{8}$ $(3 pi )/8$ and the coefficient of friction is $\frac{1}{7}$ $1/7$ , what is the maximum mass that can be pulled up at one time?