A truck pulls boxes up an incline plane. The truck can exert a maximum force of 3,600 N. If the plane's incline is pi/8 and the coefficient of friction is 9/5 , what is the maximum mass that can be pulled up at one time?

1 Answer
Mar 26, 2018

The mass is =179.6kg

Explanation:

![http://spmphysics.onlinetuition.com.my/2013/06/http://inclined-plane.html](https://useruploads.socratic.org/3SLPG4SgRIu153RhGHJq_inclined%20plane.jpg)

Resolving in the direction parallel to the plane ↗^+

Let the force exerted by the truck be F=3600N

Let the frictional force be =F_rN

The coefficient of friction mu=F_r/N=9/5

The normal force is N=mgcostheta

The angle of the plane is theta=1/8pi

The acceleration due to gravity is g=9.8ms^-2

Therefore,

F=F_r+mgsintheta

=muN+mgsintheta

=mumgcostheta+mgsintheta

m=F/(g(mucostheta+sintheta))

=3600/(9.8(9/5*cos(1/8pi)+sin(1/8pi))

=179.6kg