A truck pulls boxes up an incline plane. The truck can exert a maximum force of $4,000 N$ . If the plane's incline is $pi/3$ and the coefficient of friction is $2/3$ , what is the maximum mass that can be pulled up at one time?

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Answer 1 · 2017-07-22T06:56:40

The mass is $=340.3kg$

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Resolving in the direction parallel to the plane $↗^+$

Let the force exerted by the truck be $=FN$

Let the frictional force be $=F_rN$

The coefficient of friction $mu=F_r/N$

The normal force is $N=mgcostheta$

Therefore,

$F=F_r+mgsintheta$

$=muN+mgsintheta$

$=mumgcostheta+mgsintheta$

$m=F/(g(mucostheta+sintheta))$

$=4000/(9.8(2/3*cos(1/3pi))+sin(1/3pi))$

$=340.3kg$

A truck pulls boxes up an incline plane. The truck can exert a maximum force of 4,000 N4,000 N. If the plane's incline is pi/3 pi/3 and the coefficient of friction is 2/3 2/3 , what is the maximum mass that can be pulled up at one time?