A truck pulls boxes up an incline plane. The truck can exert a maximum force of $4, 400 N$ $4,400 N$ . If the plane's incline is $\frac{5 π}{8}$ $(5 pi )/8$ and the coefficient of friction is $\frac{3}{4}$ $3/4$ , what is the maximum mass that can be pulled up at one time?

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A truck pulls boxes up an incline plane. The truck can exert a maximum force of $4, 400 N$ $4,400 N$ . If the plane's incline is $\frac{5 π}{8}$ $(5 pi )/8$ and the coefficient of friction is $\frac{3}{4}$ $3/4$ , what is the maximum mass that can be pulled up at one time?

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Answer 1 · 2016-04-08T14:24:45

Here
Force of gravitational pull along inclined plane + force of friction = Total maximum force
If maximum mass pulled = $m k g$ $mkg$
Force of gravitational pull along inclined plane $= m g sin θ$ $=mgsintheta$
force of friction $= μ m g cos θ$ $=mumgcostheta$

$m g sin θ + μ m g cos θ = 4400$ $mgsintheta +mumg costheta =4400$

$m \times 9.8 \times (sin (π - 5 \frac{π}{8}) + \frac{3}{4} \times cos (π - 5 \frac{π}{8})) = 4400$ $mxx9.8xx(sin(pi-5pi/8)+3/4xxcos(pi-5pi/8))=4400$
$m \times 9.8 \times (sin (3 \frac{π}{8}) + \frac{3}{4} \times cos (3 \frac{π}{8})) = 4400$ $mxx9.8xx(sin(3pi/8)+3/4xxcos(3pi/8))=4400$
$m = 370.8 k g$ $m=370.8kg$

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A truck pulls boxes up an incline plane. The truck can exert a maximum force of $4, 400 N$ $4,400 N$ . If the plane's incline is $\frac{5 π}{8}$ $(5 pi )/8$ and the coefficient of friction is $\frac{3}{4}$ $3/4$ , what is the maximum mass that can be pulled up at one time?

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A truck pulls boxes up an incline plane. The truck can exert a maximum force of 4,400N4,400 N. If the plane's incline is 5π8(5 pi )/8 and the coefficient of friction is 343/4 , what is the maximum mass that can be pulled up at one time?

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A truck pulls boxes up an incline plane. The truck can exert a maximum force of $4, 400 N$ $4,400 N$ . If the plane's incline is $\frac{5 π}{8}$ $(5 pi )/8$ and the coefficient of friction is $\frac{3}{4}$ $3/4$ , what is the maximum mass that can be pulled up at one time?