A volume of helium occupies 11.0 L at a pressure of 98.0 kPa. What is the new volume if the pressure drops to 86.2 kPa?

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Answer 1 · 2016-12-18T09:01:59

The new volume is #=12.5L#

#P_1V_1= P_2V_2#

Pressure, #P_1=98.0 kPa#

Volume, #V_1=11.0L#

Pressure, #P_2=86.2kPa#

Volume, #V_2=(P_1V_1)/P_2#

#=98.0*11.0/86.2=12.5L#