A weather balloon has a maximum volume of $7.50 \cdot 10^{3}$ $7.50 * 10^3$ $L$ $L$ . The balloon contains $195$ $195$ $L$ $L$ of helium gas at a pressure of $0.993$ $0.993$ $a t m$ $atm$ . What will be the pressure when the balloon is at maximum volume?

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Answer 1 · 2017-02-22T19:46:10

Approx. $0.03*atm.........$

We use old $"Boyle's Law"$ , $P_1V_1=P_2V_2$ at constant temperature.

And we solve for $P_2=(P_1V_1)/V_2=(195*Lxx0.993*atm)/(7.5xx10^3L)$

$=2.58xx10^-2*atm.$

A weather balloon has a maximum volume of 7.50 * 10^37.50⋅1037.50 * 10^3 LLL. The balloon contains 195195195 LLL of helium gas at a pressure of 0.9930.9930.993 atmatmatm. What will be the pressure when the balloon is at maximum volume?