A wrench with a length of $12 cm$ is being used to unscrew a $3 cm$ bolt. If a torque of $5 Nm$ is needed to overcome the friction keeping the bolt in place, what is the minimum torque that must be applied to the wrench to unscrew the bolt?

Question

1680 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-13T21:24:28

The torque required to unscrew is 5Nm but the force on the wrench is 37.03N

Torque is always to the center of the rotated object.

Assuming you mean bolt diameter is 3cm, so radius is1.5cm

The torque which holds it is 5Nm which is 500N-cm

So $500/(12 +1.5)$ is the force required to unscrew the bolt.

That equals : $37.03N$

A wrench with a length of 12 cm12 cm is being used to unscrew a 3 cm3 cm bolt. If a torque of 5 Nm5 Nm is needed to overcome the friction keeping the bolt in place, what is the minimum torque that must be applied to the wrench to unscrew the bolt?