A wrench with a length of $12 c m$ $12 cm$ is being used to unscrew a $3 c m$ $3 cm$ bolt. If a torque of $5 N m$ $5 Nm$ is needed to overcome the friction keeping the bolt in place, what is the minimum torque that must be applied to the wrench to unscrew the bolt?

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Answer 1 · 2018-03-13T21:24:28

The torque required to unscrew is 5Nm but the force on the wrench is 37.03N

Torque is always to the center of the rotated object.

Assuming you mean bolt diameter is 3cm, so radius is1.5cm

The torque which holds it is 5Nm which is 500N-cm

So $\frac{500}{12 + 1.5}$ $500/(12 +1.5)$ is the force required to unscrew the bolt.

That equals : $37.03 N$ $37.03N$

A wrench with a length of 12 cm12cm12 cm is being used to unscrew a 3 cm3cm3 cm bolt. If a torque of 5 Nm5Nm5 Nm is needed to overcome the friction keeping the bolt in place, what is the minimum torque that must be applied to the wrench to unscrew the bolt?