A wrench with a length of $48 c m$ $48 cm$ is being used to unscrew a $6 c m$ $6 cm$ bolt. If a torque of $72 N m$ $72 Nm$ is needed to overcome the friction keeping the bolt in place, what is the minimum torque that must be applied to the wrench to unscrew the bolt?

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Answer 1 · 2018-02-13T20:24:31

The force applied to the wrench must be $\geq 150 N$ $>= 150N$

Torque is $τ = F r sin (θ)$ $\tau=FrSin(\theta)$

The torque value in this problem is similar to static friction. Once it's overcome, the bolt will turn.

$72 N m = F \cdot .48 m$ $72Nm=F*.48m$ , therefore $F = 150 N$ $F =150N$

A wrench with a length of 48cm48 cm is being used to unscrew a 6cm6 cm bolt. If a torque of 72Nm72 Nm is needed to overcome the friction keeping the bolt in place, what is the minimum torque that must be applied to the wrench to unscrew the bolt?