A wrench with a length of $54 c m$ $54 cm$ is being used to unscrew a $6 c m$ $6 cm$ bolt. If a torque of $90 N m$ $90 Nm$ is needed to overcome the friction keeping the bolt in place, what is the minimum torque that must be applied to the wrench to unscrew the bolt?

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Answer 1 · 2018-01-07T16:56:53

'What is the minimum force that must be applied'

$16 \frac{2}{3} Newtons$ $16 2/3" Newtons"$

Did you know that you can and may treat units of measurement in the same way you do the numbers

Known: $54 c m = 0.54 m$ $54cm = 0.54m$

Let the unknown applied force be $x$ $x$ Newtons

$0.54 m \times x N = 90 N m$ $0.54 m xx xN=90 Nm$

Divide both sides by $0.54 m$ $0.54 m$

$(0.54m)/(0.54m)xx xN=(90xxNxxcancel(m))/(0.54xxcancel(m))$

$color(white)("dd")1color(white)("ddd")xx xN=16 2/3N$

A wrench with a length of 54 cm54cm54 cm is being used to unscrew a 6 cm6cm6 cm bolt. If a torque of 90 Nm90Nm90 Nm is needed to overcome the friction keeping the bolt in place, what is the minimum torque that must be applied to the wrench to unscrew the bolt?