Question

A balloon that had a volume of 3.50 L at 25.0 °C is placed in a hot room at 40.0 °C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?

Answer 1

3.68 liters to three significant numbers.

Explanation:

This is a Charles Law problem

`V_1/T_1 = V_2/T_2`

`V_1 = "3.5 L"`,

`T_1 = 25 + 273 = "298 K"` ,

`V_2 = "unknown L"`,

`T_2 = 40 + 273 = "313 K"`,

so

`("3.5 L")/("298 K") = V_2/("313 K")` .

This gives

`("3.5 L") xx ("313 K")/("298 K") = V_2`.

`=> "3.68 L" = V_2`