A balloon that had a volume of 3.50 L at 25.0 °C is placed in a hot room at 40.0 °C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?
1 Answer
Jun 8, 2017
3.68 liters to three significant numbers.
Explanation:
This is a Charles Law problem
V_1/T_1 = V_2/T_2
V_1 = "3.5 L" ,
T_1 = 25 + 273 = "298 K" ,
V_2 = "unknown L" ,
T_2 = 40 + 273 = "313 K" ,
so
("3.5 L")/("298 K") = V_2/("313 K") .
This gives
("3.5 L") xx ("313 K")/("298 K") = V_2 .
=> "3.68 L" = V_2