Alkanes have the general molecular formula $C_nH_(2n+2)$ . Thus, when $n= 1$ , the alkane is $CH_4$ , when $n = 2$ , the alkane is $C_2H_6$ etc. If an alkane has a molar mass between 140 and 150, what is the alkene?

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Answer 1 · 2016-12-01T14:37:13

The required alkane is a Decane $(C_10H_22)$ .

This is a simple calculation.
The general formula for alkanes is $C_n H_(2n+2)$ .

So, an alkane having 10 carbon atoms will surely have 22 hydrogen atoms, according to the given formula.

So, the molar mass of decane is equal to:
$=(10xx12)+(22xx1)$ grams.
$=142$ grams.

Now, 142 lies between 140 & 150.
So, the alkane is Decane.

Alkanes have the general molecular formula C_nH_(2n+2)C_nH_(2n+2). Thus, when n= 1n= 1, the alkane is CH_4CH_4, when n = 2n = 2, the alkane is C_2H_6C_2H_6 etc. If an alkane has a molar mass between 140 and 150, what is the alkene?