#P_(CO_2)# = #0.288"mmHg"# if #%CO_2# is mole percent. If #%CO_2# is weight percent then one will need the mass values of the other components of the air mixture.
Explanation:
Given #0.038%# (mole/mole) => #X_(CO_2)# = #(0.0038"mole" CO_2)/(100"moles"AIR")# = #0.00038#