An archer shoots an arrow at an angle of 30 degrees from a height of 1.4m. If it took 1.6 seconds for the arrow to hit the target, which is 1.4m tall, what was the arrow's initial speed? How far away was the target?
1 Answer
Sep 21, 2015
(a).
(b).
Explanation:
(a).
To get the initial vertical component of velocity we can use:
This becomes:
(0.8 = 1.6/2 - which is the time taken to reach the zenith)
(b).
The distance covered = speed x time
The horizontal component of the velocity
So the distance
To get the height reached:
So the total height above the ground
It reaches maximum height 1/2 way through the flight so it will be
