An engineer pumps 200.50 grams of carbon monoxide (CO) gas into a cylinder capacity of 120.0 L. What is pressure inside the cylinder at 45.0°C?

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An engineer pumps 200.50 grams of carbon monoxide (CO) gas into a cylinder capacity of 120.0 L. What is pressure inside the cylinder at 45.0°C?

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Answer 1 · 2016-04-29T06:37:37

$P = \frac{n R T}{V}$ $P=(nRT)/V$ , approx. $1.6$ $1.6$ $a t m$ $atm$

Explanation:

$n_{C O}$ $n_(CO)$ $=$ $=$ $\frac{200.50 \cdot g}{28.01 \cdot g \cdot m o l^{- 1}}$ $(200.50*g)/(28.01*g*mol^-1)$ $=$ $=$ $7.158 \cdot m o l$ $7.158*mol$

$Pressure = \frac{7.158 \cdot m o l \times 0.0821 \cdot L \cdot a t m \cdot K^{- 1} \cdot m o l^{- 1} \times 318 \cdot K}{120.0 \cdot L}$ $"Pressure"=(7.158*molxx0.0821*L*atm*K^-1*mol^-1xx318*K)/(120.0*L)$

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An engineer pumps 200.50 grams of carbon monoxide (CO) gas into a cylinder capacity of 120.0 L. What is pressure inside the cylinder at 45.0°C?

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