An experiment produced 0.10 g $CO_2$ , with a volume of 0.056 L at STP. If the accepted density of $CO_2$ at STP is 1.96 g/L, what is the approximate percent error?

Question

2863 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-15T02:32:09

The percent error is $8.2%$ .

You have to compare the density of $"CO"_2$ produced experimentally at STP to the accepted density of $"CO"_2$ at STP.

$"density"="mass"/"volume"$

You are given the mass and volume of the experimentally produced $"CO"_2:$ $"mass"="0.10 g";$ $"volume"="0.056 L"$

Insert your data into the density formula and solve.

$"density CO"_2"="(0.10"g CO"_2)/(0.056"L CO"_2)="1.8 g/L"$

$"Percent error"=abs(("experimental value"-"accepted value")/("accepted value"))xx100$

Insert your data into the percent error equation.

$"Percent error"=abs(("1.8 g/L"-"1.96 g/L")/("1.96 g/L"))xx100="8.2%$ (rounded to two significant figures)

An experiment produced 0.10 g CO_2CO_2, with a volume of 0.056 L at STP. If the accepted density of CO_2CO_2 at STP is 1.96 g/L, what is the approximate percent error?