An isosceles triangle has sides A, B, and C, such that sides A and B have the same length. Side C has a length of $12$ and the triangle has an area of $42$ . What are the lengths of sides A and B?

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Answer 1 · 2018-06-20T14:56:10

Area= $1/2 xx base xx height$

$42=1/2 xx 12 xx height$

$height=7$

the height will bisect the base and create two right triangles where the hypotenuse of each will be the lengths A and B

Using Pythagoras $a^2+b^2=c^2$

$6^2+7^2=A^2$

$36+49=A^2$

$A=B=sqrt 85$

An isosceles triangle has sides A, B, and C, such that sides A and B have the same length. Side C has a length of 12 12 and the triangle has an area of 42 42 . What are the lengths of sides A and B?