An isosceles triangle has sides A, B, and C, such that sides A and B have the same length. Side C has a length of $5$ and the triangle has an area of $40$ . What are the lengths of sides A and B?

Question

1447 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-30T11:11:39

$sides A and B = 16.194$

Let h = height of the triangle
Area = $1/2xx5xxh=40$
$h=16$
side A = side B = $sqrt(16^2+(5/2)^2) = 16.194$

An isosceles triangle has sides A, B, and C, such that sides A and B have the same length. Side C has a length of 5 5 and the triangle has an area of 40 40 . What are the lengths of sides A and B?