An object initially at rest moves along x axis subjected to an acceleration which varies with time according to relation a=2t+5 it initial velocity of particle is 5m/s then its velocity after 2 second will be?

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Answer 1 · 2017-06-11T16:06:21

The velocity is #=19ms^-1#

The velocity is the integral of the acceleration

#a(t)=2t+5#

#v(t)=int(2t+5)dt#

#=2/2t^2+5t+C#

When #t=0#, #v(0)=5#

#v(0)=0+0+C=5#

#C=5#

#v(t)=t^2+5t+5#

So,

#v(2)=2^2+5*2+5=4+10+5=19ms^-1#