Question

An object is moving at a velocity or 8.8 m/s. It accelerates to a velocity of 35 m/s over a time of 6.3 s. What acceleration did it experience?

Answer 1

The acceleration is `"4.2 m/s"^2"`.

Explanation:

Acceleration is the change in velocity over a periodic of time.

`a=(v_f-v_i)/(Deltat)`, where `a` is acceleration, `v_f` is final velocity, `v_i` is initial velocity, and `Deltat` is time interval.

Known
`v_f=35"m/s"`
`v_i=8.8"m/s"`
`Delta t=6.3"s"`

Unknown
`a`

Equation

`a=(v_f-v_i)/(Deltat)`

Solution

`a=(35"m/s"-8.8"m/s")/(6.3"s")=`

`a=(26.2"m/s")/(6.3"s")="4.2 m/s/s=4.2 m/s"^2"`