An object of length #2cm# is placed at a distance of #2.5*f# from a concave mirror where f is its focal length. what is the length of the IMAGE?

length is provided and not the hieght.just need the length of image. PLease as fast as possible.

1 Answer
Nov 12, 2016

The conjugate foci relation of spherical mirror is

#1/v+1/u=1/f......(1)#

Where

#v->"Image distance"=?#

#u->"Object distance"=-2.5f#

#f->"Focal length"=-f#

So inserting the values in equation (1)

#1/v-1/(2.5f)=-1/f#

#=>1/v-1/(2.5f)=-1/f#

#=>1/v=-1/f+1/(2.5f)#

#=>1/v=-1/f+2/(5f)=(-5+2)/(5f)=-3/(5f)#

#=>v=-(5f)/3#

Negative means real and inverted image

Now Magnification #m-=v/u=((5f)/3)/((5f)/2)=2/3#

So #"size of image"=mxx"size of object"=2/3xx2cm=4/3cm #