An object, previously at rest, slides 15 m15m down a ramp, with an incline of pi/3 π3, and then slides horizontally on the floor for another 6 m6m. If the ramp and floor are made of the same material, what is the material's kinetic friction coefficient?

1 Answer
Apr 9, 2016

~~0.960.96

Explanation:

Here length of the ramp (l)= 15m

Angle of inclination of the ramp theta = pi/3θ=π3
Height of the object from horizontal floor,h=lsinthetah=lsinθ
If mass ofthe body is m kgmkg
The initial gravitational potential energy of the body PE=mgh=mglsintheta=15mgsintheta JPE=mgh=mglsinθ=15mgsinθJ
The normal reaction acting on the body when it is sliding down the ramp is N_r=mgcosthetaNr=mgcosθ
and the corresponding frictional force F_r=muN_r=mumgcosthetaFr=μNr=μmgcosθ
where mu=μ=coefficient of kinetc friction
work done against frictional force when sliding down the ramp W_1=F_rxxl=mumgcosthetaxx15JW1=Fr×l=μmgcosθ×15J

when the body slides on horizontal force,then normal reaction N_f=mgNf=mg and corresponding frictional force F_f=muN_f=mumgFf=μNf=μmg
work done against frictional force when sliding 6m along floor
W_2=F_fxx6=6mumgJW2=Ff×6=6μmgJ
Now applying conservation of mechanical energy we can write

The initial KE being zero
Initial PE = total work done against frictional force =W_1+W_2=W1+W2
:. 15mgsintheta=W_1+W_2
=>15mgsintheta=15mumgcostheta+6mumg
=>mu=(15sintheta)/(6+15costheta)=(5sin(pi/3))/(2+5cos(pi/3))
=(5xxsqrt3/2)/(2+5xx1/2)=(2.5xxsqrt3)/4.5=5/9xxsqrt3=~~0.96