An object with a mass of $1 k g$ $1 kg$ is hanging from an axle with a radius of $16 m$ $16 m$ . If the wheel attached to the axle has a radius of $72 m$ $72 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2018-01-13T07:19:57

The force is $F = 2.18 N$ $F=2.18N$

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The load is $L = 1 g N$ $L=1gN$

The radius of the axle is $r = 16 m$ $r=16m$

The radius of the wheel is $R = 72 m$ $R=72m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 72 = 1 g \cdot 16$ $F*72=1g*16$

$F = \frac{1 g \cdot 16}{72} = 2.18 N$ $F=(1g*16)/72=2.18N$

The force is $F = 2.18 N$ $F=2.18N$

An object with a mass of 1kg1 kg is hanging from an axle with a radius of 16m16 m. If the wheel attached to the axle has a radius of 72m72 m, how much force must be applied to the wheel to keep the object from falling?