An object with a mass of $1 k g$ $1 kg$ is lying still on a surface and is compressing a horizontal spring by $1 m$ $1 m$ . If the spring's constant is $15 \frac{k g}{s^{2}}$ $15 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-12-30T09:14:54

The coefficient of static friction is $= 1.53$ $=1.53$

The mass is $m = 1 k g$ $m=1kg$

The compression of the spring is $x = 1 m$ $x=1m$

The spring constant is $k = 15 k g s^{- 2}$ $k=15kgs^-2$

The reaction of the spring is $R = k x = 15 \cdot 1 = 15 N$ $R=kx=15*1=15N$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

The normal reaction of the object is $N = m g = 1 \cdot 9.8 = 9.8 N$ $N=mg=1*9.8=9.8N$

The coefficient of static friction is

$μ_{s} = \frac{R}{N} = \frac{15}{9.8} = 1.53$ $mu_s=R/N=15/9.8=1.53$

An object with a mass of 1kg 1 kg is lying still on a surface and is compressing a horizontal spring by 1m1 m. If the spring's constant is 15kgs2 15 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?