An object with a mass of 1 kg is pushed along a linear path with a kinetic friction coefficient of u_k(x)= 3x^2-2x+12 . How much work would it take to move the object over #x in [1, 3], where x is in meters?

1 Answer
Feb 13, 2016

W=412,02J

Explanation:

W=int_1^3 mg*(3x^2-2x+12)*d x
W=mg int_1^3(3x^2-2x+12)*d x
W=mg[3*x^3/3-2*x^2/2+12x]_1^3
W=mg[[27-9+36]-[1-1+12]]
W=mg[42]
W=1*9,81*42
W=412,02J