An object with a mass of 1 kg is pushed along a linear path with a kinetic friction coefficient of u_k(x)= 3x^2+x+2 . How much work would it take to move the object over #x in [1, 3], where x is in meters?

1 Answer
Feb 18, 2016

W=335,54J

Explanation:

F_f=u_k*N
F_f=" Friction force"
"N:Normal force to the contacting surfaces"
N=m*g " m:mass of object, g:acceleration of gravity"
F_f=u_k*m*g
W=int_1^3 F_f*d x
W:"work doing by Friction force"
W=int_1^3 u_k*m*g*d x
W=mg int_1^3 (3x^2+x+2)d x
W=mg[3*1/3x^3+1/2x^2+2x ]_1^3+C
W=1*9,81[x^3+1/2x^2+2x]_1^3 +C
u_k(0)=2 ; then C=2
W=9,81([27+4,5+6]-[1+0,5+2])+2
W=9,81(37,5-3,5)+2
W=9,81*34+2
W=335,54J