An object with a mass of $12 kg$ is lying still on a surface and is compressing a horizontal spring by $3/2 m$ . If the spring's constant is $6 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

Question

1568 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-28T05:29:12

$\mu_s=0.0765$

Given that $m=12kg$ , $k=6kgs^-2$ , $deltax=3/2m$

The object is said to be lying still and hence the normal force times the coefficient of friction is the maximum restoring force applied on the body.

So, $kx=\mu_smg\impliescancel{6}^1*3/cancel{2}^1=\mu_s*9.8*cancel{12}^4$
So, $\mu_s=3/(4*9.8)$

I reduced the value up in the answer part.

An object with a mass of 12 kg 12 kg is lying still on a surface and is compressing a horizontal spring by 3/2 m3/2 m. If the spring's constant is 6 (kg)/s^2 6 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?