An object with a mass of $12 k g$ $12 kg$ is on a surface with a kinetic friction coefficient of $1$ $1$ . How much force is necessary to accelerate the object horizontally at $3 \frac{m}{s^{2}}$ $3 m/s^2$ ?

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Answer 1 · 2018-03-21T01:49:17

$36 N$ $"36 N"$

From Newton’s second law,

$F = ma$ $"F = ma"$

$F = 12 kg \times {3 m/s}^{2} = 36 N$ $"F" = "12 kg" × "3 m/s"^2 = "36 N"$

An object with a mass of 12kg12 kg is on a surface with a kinetic friction coefficient of 1 1 . How much force is necessary to accelerate the object horizontally at 3ms2 3 m/s^2?