An object with a mass of $12 k g$ $12 kg$ is revolving around a point at a distance of $12 m$ $12 m$ . If the object is making revolutions at a frequency of $17 H z$ $17 Hz$ , what is the centripetal force acting on the object?

Question

1396 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-06T11:22:07

The centripetal force is $= 1642934 N$ $=1642934N$

The cetripetal force is

$F = \frac{m v^{2}}{r} = m r ω^{2}$ $F=(mv^2)/r=mromega^2$

The mass is $m = 12 k g$ $m=12kg$

The radius is $r = 12 m$ $r=12m$

The frequency is $f = 17 H z$ $f=17Hz$

The angular velocity is $ω = 2 π f = 2 π \cdot 17 = 34 π r a d s^{- 1}$ $omega=2pif=2pi*17=34pirads^-1$

So,

$F = 12 \cdot 12 \cdot {(34 π)}^{2} = 1642934 N$ $F=12*12*(34pi)^2=1642934N$

An object with a mass of 12 kg12kg12 kg is revolving around a point at a distance of 12 m12m12 m. If the object is making revolutions at a frequency of 17 Hz17Hz17 Hz, what is the centripetal force acting on the object?