An object with a mass of $12 k g$ $12 kg$ is revolving around a point at a distance of $6 m$ $6 m$ . If the object is making revolutions at a frequency of $1 H z$ $1 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2018-05-18T05:45:57

The centripetal force is $= 2842.4 N$ $=2842.4N$

The centripetal force is

$F = m r ω^{2}$ $F=mromega^2$

The mass of the object is

$m = 12 k g$ $m=12kg$

The radius of the circle is

$r = 6 m$ $r=6m$

The frequency of rotation is

$f = 1 H z$ $f=1Hz$

The angular velocity is

$ω = 2 π f = 2 \cdot π \cdot 1 = 2 π r a d s^{- 1}$ $omega=2pif=2*pi*1=2pirads^-1$

Therefore,

the centripetal force is

$F = 12 \cdot 6 \cdot {(2 π)}^{2} = 2842.4 N$ $F=12*6*(2pi)^2=2842.4N$

An object with a mass of 12kg12 kg is revolving around a point at a distance of 6m6 m. If the object is making revolutions at a frequency of 1Hz1 Hz, what is the centripetal force acting on the object?