An object with a mass of 14 kg is lying still on a surface and is compressing a horizontal spring by 70 c m. If the spring's constant is 2 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?

1 Answer
Feb 19, 2018

The coefficient of static friction is =0.01

Explanation:

The mass is m=14kg

The compression of the spring is x=0.7m

The spring constant is k=2kgs^-2

The reaction of the spring is R=kx=2*0.7=1.4N

The acceleration due to gravity is g=9.8ms^-2

The normal reaction of the object is

N=mg=14*9.8=137.2N

The coefficient of static friction is

mu_s=R/N=1.4/137.2=0.01