An object with a mass of $15 k g$ $15 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{6} m$ $5/6 m$ . If the spring's constant is $24 \frac{k g}{s^{2}}$ $24 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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An object with a mass of $15 k g$ $15 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{6} m$ $5/6 m$ . If the spring's constant is $24 \frac{k g}{s^{2}}$ $24 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2016-02-13T13:53:47

coefficient of static friction 0.1361

Explanation:

The horizontal force exerted on the object = force con.x compression = $24 \cdot \frac{5}{6}$ $24*5/6$ =20 N
Now $μ m g =$ $mumg=$ the force applied
coefficient of static friction, $μ =$ $mu=$ $\frac{20}{m g}$ $20/(mg)$ = $\frac{20}{15 \cdot 9.8}$ $20/(15*9.8)$ = 0.1361

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An object with a mass of $15 k g$ $15 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{6} m$ $5/6 m$ . If the spring's constant is $24 \frac{k g}{s^{2}}$ $24 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Explanation:

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An object with a mass of 15kg15 kg is lying still on a surface and is compressing a horizontal spring by 56m5/6 m. If the spring's constant is 24kgs224 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?

1 Answer

Explanation:

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An object with a mass of $15 k g$ $15 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{6} m$ $5/6 m$ . If the spring's constant is $24 \frac{k g}{s^{2}}$ $24 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?