An object with a mass of 15kg is on a ramp at an incline of π8. If the object is being pushed up the ramp with a force of 9N, what is the minimum coefficient of static friction needed for the object to remain put?
1 Answer
Apr 1, 2017
The coefficient of static friction is obtained from the ratio of the Normal force to the force parallel to the incline, in this case 9N in a direction up the incline.
Explanation:
The forces involved are:
- force of gravity on the 15 kg block, which is
15kg⋅9.8ms−2=147N - Normal force on the block perpendicular to the incline, which is
147⋅cos(π6)=147N - force on the block parallel to the incline which is
147⋅sin(π6)=1.34N
If there is a force of 9N pushing up the incline, and a parallel force of 1.34 N in the opposite direction, then the net force up the incline is7.66N .
The coefficient of static friction therefore, is7.66147=0.52