An object with a mass of 15 kg15kg is revolving around a point at a distance of 16 m16m. If the object is making revolutions at a frequency of 15 Hz15Hz, what is the centripetal force acting on the object?

1 Answer
Jan 29, 2017

I got:
F_c=1,932,407NFc=1,932,407N

Explanation:

We start remembering that centripetal force is:

F_c=mv^2/rFc=mv2r

To evaluate the velocity we use frequency and we consider that our object is making 15 revolutions in 1 second so we get that it takes:
1/15=0.07s115=0.07s to complete one revolution that represents a distance along a circle of 2pir=2*3.14*16=100.53~~100.5m2πr=23.1416=100.53100.5m.
Velocity will then be: v=100.5/0.07=1435.7m/sv=100.50.07=1435.7ms

So we get:
F_c=15*(1435.7)^2/16=1,932,407NFc=15(1435.7)216=1,932,407N