An object with a mass of $16 kg$ is lying still on a surface and is compressing a horizontal spring by $2/3 m$ . If the spring's constant is $4 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-04-24T06:23:47

The coefficient of static friction is $=0.02$

The force of friction is

$F_r=k*Deltax$

The spring constant is $k=4kgs^-2$

The distance is $Deltax=2/3m$

Therefore,

$F_r=4*2/3=8/3N$

The coefficient of static friction is

$mu_s=F_r/N$

The normal force is $N=mg=(16g) N$

So,

$mu_s=(8/3)/(16g)=0.02$

An object with a mass of 16 kg 16 kg is lying still on a surface and is compressing a horizontal spring by 2/3 m2/3 m. If the spring's constant is 4 (kg)/s^2 4 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?