An object with a mass of $160 g$ $160 g$ is dropped into $880 m L$ $880 mL$ of water at $0^{\circ} C$ $0^@C$ . If the object cools by $120^{\circ} C$ $120 ^@C$ and the water warms by $5^{\circ} C$ $5 ^@C$ , what is the specific heat of the material that the object is made of?

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An object with a mass of $160 g$ $160 g$ is dropped into $880 m L$ $880 mL$ of water at $0^{\circ} C$ $0^@C$ . If the object cools by $120^{\circ} C$ $120 ^@C$ and the water warms by $5^{\circ} C$ $5 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2016-02-03T11:41:13

$1004.35 j k g^{- 1} K^{- 1}$ $1004.35jkg^(-1)K^(-1)$

Explanation:

suppose,
the specific heat of the object is $S$ $S$
now,
we know,
$1 m l$ $1ml$ water= $1 g m$ $1gm$
$:.880ml$ water= $880gm$
$=0.88kg$
and we know,
heat loss= heat gain
$0.16Sxx(120-5)=0.88xx4200xx5$
$=>18.4S=18480$
$=>S=1004.35jkg^(-1)K^(-1)$

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An object with a mass of $160 g$ $160 g$ is dropped into $880 m L$ $880 mL$ of water at $0^{\circ} C$ $0^@C$ . If the object cools by $120^{\circ} C$ $120 ^@C$ and the water warms by $5^{\circ} C$ $5 ^@C$ , what is the specific heat of the material that the object is made of?

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Explanation:

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An object with a mass of 160 g160g160 g is dropped into 880 mL880mL880 mL of water at 0^@C0∘C0^@C. If the object cools by 120 ^@C120∘C120 ^@C and the water warms by 5 ^@C5∘C5 ^@C, what is the specific heat of the material that the object is made of?

1 Answer

Explanation:

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An object with a mass of $160 g$ $160 g$ is dropped into $880 m L$ $880 mL$ of water at $0^{\circ} C$ $0^@C$ . If the object cools by $120^{\circ} C$ $120 ^@C$ and the water warms by $5^{\circ} C$ $5 ^@C$ , what is the specific heat of the material that the object is made of?