An object with a mass of $18 k g$ $18 kg$ is hanging from an axle with a radius of $15 c m$ $15 cm$ . If the wheel attached to the axle has a radius of $45 c m$ $45 cm$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-12-12T06:37:44

The force is $= 58.8 N$ $=58.8N$

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The load is $L = 18 g N$ $L=18gN$

The radius of the axle is $r = 0.15 m$ $r=0.15m$

The radius of the wheel is $R = 0.45 m$ $R=0.45m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 0.45 = 18 g \cdot 0.15$ $F*0.45=18g*0.15$

$F = \frac{18 g \cdot 0.15}{0.45} = 58.8 N$ $F=(18g*0.15)/0.45=58.8N$

The force is $F = 58.8 N$ $F=58.8N$

An object with a mass of 18 kg18kg18 kg is hanging from an axle with a radius of 15 cm15cm15 cm. If the wheel attached to the axle has a radius of 45 cm45cm45 cm, how much force must be applied to the wheel to keep the object from falling?