An object with a mass of $18 k g$ $18 kg$ is hanging from an axle with a radius of $16 c m$ $16 cm$ . If the wheel attached to the axle has a radius of $2 c m$ $2 cm$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-06-03T06:50:10

The force is $= 1411.2 N$ $=1411.2N$

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The load L=(18g)N#

Radius of axle $r = 0.16 m$ $r=0.16m$

Radius of wheel $R = 0.02 m$ $R=0.02m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 0.02 = 18 \cdot g \cdot 0.16$ $F*0.02=18*g*0.16$

$F = \frac{18 \cdot g \cdot 0.16}{0.02} = 1411.2 N$ $F=(18*g*0.16)/0.02=1411.2N$

The force is $= 1411.2 N$ $=1411.2N$

An object with a mass of 18kg18 kg is hanging from an axle with a radius of 16cm16 cm. If the wheel attached to the axle has a radius of 2cm2 cm, how much force must be applied to the wheel to keep the object from falling?