An object with a mass of $18 k g$ $18 kg$ is on a surface with a kinetic friction coefficient of $2$ $2$ . How much force is necessary to accelerate the object horizontally at $17 \frac{m}{s^{2}}$ $17 m/s^2$ ?

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Answer 1 · 2016-10-22T06:18:39

Given
$m \to Mass of the object = 18 k g$ $m->"Mass of the object"=18kg$

$a \to Accelerationof the object = 17 \frac{m}{s^{2}}$ $a->"Accelerationof the object"=17m/s^2$

$μ_{k} \to Coefficient of kinetic friction = 2$ $mu_k->"Coefficient of kinetic friction"=2$

Let the force necessary to maintain the required acceleration be F

$F = m \times a + μ_{k} \times m \times g$ $F= mxxa+mu_kxxmxxg$

$\Rightarrow F = 18 \times 17 + 2 \times 18 \times 9.8 = 658.8 N$ $=>F= 18xx17+2xx18xx9.8=658.8N$

An object with a mass of 18kg18 kg is on a surface with a kinetic friction coefficient of 2 2 . How much force is necessary to accelerate the object horizontally at 17ms2 17 m/s^2?