An object with a mass of $2 k g$ $2 kg$ is hanging from an axle with a radius of $2 m$ $2 m$ . If the wheel attached to the axle has a radius of $28 m$ $28 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2018-01-05T18:41:13

The force is $F = 1.4 N$ $F=1.4N$

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The load is $L = 2 g N$ $L=2gN$

The radius of the axle is $r = 2 m$ $r=2m$

The radius of the wheel is $R = 28 m$ $R=28m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 28 = 2 g \cdot 2$ $F*28=2g*2$

$F = \frac{2 g \cdot 2}{28} = 1.4 N$ $F=(2g*2)/28=1.4N$

The force is $F = 1.4 N$ $F=1.4N$

An object with a mass of 2 kg2kg2 kg is hanging from an axle with a radius of 2 m2m2 m. If the wheel attached to the axle has a radius of 28 m28m28 m, how much force must be applied to the wheel to keep the object from falling?