An object with a mass of $2 k g$ $2 kg$ is hanging from an axle with a radius of $24 c m$ $24 cm$ . If the wheel attached to the axle has a radius of $18 c m$ $18 cm$ , how much work would it take to turn the wheel a length equal to the circumference of the axle?

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Answer 1 · 2017-06-11T05:23:25

The work is $= 39.41 J$ $=39.41J$

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The load L=(2g)N#

Radius of axle $r = 0.24 m$ $r=0.24m$

Radius of wheel $R = 0.18 m$ $R=0.18m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 0.18 = 2 \cdot g \cdot 0.24$ $F*0.18=2*g*0.24$

$F = \frac{2 \cdot g \cdot 0.24}{0.18} = 26.13 N$ $F=(2*g*0.24)/0.18=26.13N$

The force is $= 26.13 N$ $=26.13N$

The distance is $d = 2 \cdot π \cdot 0.24 m$ $d=2*pi*0.24m$

The work is

$W = F \cdot d = 26.13 \cdot 0.48 π = 39.41 J$ $W=F*d=26.13*0.48pi=39.41J$

An object with a mass of 2kg2 kg is hanging from an axle with a radius of 24cm24 cm. If the wheel attached to the axle has a radius of 18cm18 cm, how much work would it take to turn the wheel a length equal to the circumference of the axle?