An object with a mass of $2 k g$ $2 kg$ is hanging from an axle with a radius of $24 c m$ $24 cm$ . If the wheel attached to the axle has a radius of $36 c m$ $36 cm$ , how much work would it take to turn the wheel a length equal to the circumference of the axle?

Question

1288 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-21T18:35:31

The work is $= 19.7 J$ $=19.7J$

enter image source here

The load $L = (2 g) N$ $L=(2g)N$

Radius of axle $r = 0.24 m$ $r=0.24m$

Radius of wheel $R = 0.36 m$ $R=0.36m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 0.36 = 2 \cdot g \cdot 0.24$ $F*0.36=2*g*0.24$

$F = \frac{2 \cdot g \cdot 0.24}{0.36} = 13.1 N$ $F=(2*g*0.24)/0.36=13.1N$

The force is $F = 13.1 N$ $F=13.1N$

The distance is $d = 2 π r = 2 π \cdot 0.24 = 0.48 π$ $d=2pir=2pi*0.24=0.48pi$

The work is $W = F d = 13.1 \cdot 0.48 π = 19.7 J$ $W=Fd=13.1*0.48pi=19.7J$

An object with a mass of 2kg2 kg is hanging from an axle with a radius of 24cm24 cm. If the wheel attached to the axle has a radius of 36cm36 cm, how much work would it take to turn the wheel a length equal to the circumference of the axle?